probability que - aprna

[ArchivalUser]

and also...this is an autosomal recessive disease...since her hubby has it...autosomal recessive can be present as aa and Aa?

what is the difference?

[ArchivalUser]

okay sorry i fell asleep last night since i was up practically all day and night studying.... the reason why i used hardy-weinberg was because the INITIAL question sounded completely random about mating and didn't state any migration... it was just a general population a husband with wife and husband seem to b homozygous for disease wife seem to be heterozygous and child probability = ?

q-q = 1
p-q = 1/3
p-p = 1
___________
1*1/3*1=1/3

maybe my concept was completely off but that was the understanding i took from it.... but once again the great @MARYAM2009 always to the rescue THANKS A MILL!!

[ArchivalUser]

If "A" refers to the normal gene and "a" is the mutated gene, then:

"Aa" is the carrier state or genotype.....carries one normal and one abnormal gene but does not exhibit the disease

"aa" is the homozygous disease state....mutation in both genes and exhibits the disease

In contrast, in an autosomal dominant disease, a "carrier" will exhibit the disease because it is a dominant mutation.

I hope I understood your question

[ArchivalUser]

My post is for @usmlemania2011

[ArchivalUser]

@psychmledr---thanks a bunch!!

:-)

[ArchivalUser]

@usmlemania: You are welcome