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cystic fibrosis,plz explain - aprna
#1
q-in a small city with stable population,the carrier frequency for CF is 1/30 in caucasian, in nearby community the CF carrier frequency is 1/100.what is the probability that a child born to a mother from the caucasian community and father from asian community will suffer from disease.

a-1/900
b-1/1000
c-1/3000
d-1/6000
e-1/12000

please answer and explain your answer.thank you
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#2
E....
For mother carrier state = 1/30....,for child to have disease allele from mother = 1/2
for father carrier state = 1/100 ....for child to have disease allele from father = 1/2
For the child will suffer from disease = 1/30into1/2into/1/100into1/2 = 1/12000
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#3
EE?
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#4
@thein7thein-thank you ,ans is e

what about other options.if they are going to ask carrier rate?
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#5
CF = autosomal recessive = 25% chance of disease and 50% carrier ... carrier does not state disease state.

mother = carrier = 50% chance of transfering disease of 1/30
father = carrier = 50% chance of transfering disease of 1/100
so child with disease being a carrier = 1/3000

child having the disease = 1/4 since its autosomal recessive
so carrier 1/3000 x 1/4 disease = 1/12000

answer : E
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#6
mother = carrier
father = carrier

Key: C= Carrier

mother:
chromosome 1: Xx = normal
chromosome 2: Xc = carrier

father:
chromosome 1: Xy = normal
chromosome 2: Xc = carrier

child 1: Xx + Xy = normal
child 2: Xx + Xc = carrier
child 3: Xc + Xy = carrier
child 4: Xc + Xc = Diseased....
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#7
@zen786,thanks a lot.
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#8
welcome =D
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#9
@zen786 u could u please explain why its 1/4, do u mean how 2/4 are carrier, 1/4 is homozygous, and 1/4 is diseased? is that were u got the 1/4??
sorry i am a bit confused...
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#10
@zen786 u could u please explain why its 1/4, do u mean how 2/4 are carrier, 1/4 is homozygous, and 1/4 is diseased? is that were u got the 1/4??
sorry i am a bit confused...
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