question...................3 - sayess

[ArchivalUser]

http://i.imgur.com/b6hHXpR.png?1

[ArchivalUser]

E. ty

[ArchivalUser]

AA
Thanks

[ArchivalUser]

Disease with BB = 20
No disease with BB = 70
Hence, Odds of getting disease with BB = 20/70

Disease without BB = 30
No Disease without BB = 40
Hence, Odds of getting disease without BB = 30/40

Odds of getting disease with BB vs Odds of getting disease without BB = (20/70) /(30/40)
= 20 * 40/ 70*30

[ArchivalUser]

Also, by constructing 2 by 2 table,
AD/BC.
A is disease with B blockers.

[ArchivalUser]

Yes Agree to Medicus A s right...E s for RR..Just messed it up..Thanks.

[ArchivalUser]

"A" is the right ans